Physics Problem! Who can solve it??

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septoid2

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It seems so easy yet is impossible to solve for me, maybe one of you guys can get it.

Water drips from a nozzle of the shower onto the floor 2.0m below. The drops fall at regular intervals of time, the first drop hitting the ground as the fourth leaves the nozzle. Find the locations of the second and third drops when the first hits the floor.

Any help would be appreciated!
 
Wouldn't it be the third one is 1 1/3 meters from the ground and the second one is 2/3 meters? Doesn't make sense seeing as how (on earth) the drop would be accelerating a 9.8 meters per second. So it wouldn't be at the same intervals of distance over time, but I guess it's just a theoretical science question.
 
It all comes down to a = dv/dt and v = dr/dt.

a is constant = 9.8m/s^2

solving by integration you can obtain the time it took the first drop to hit the ground. then you divide the total time by 3 equal intervals, which represent the current location of drops #2 and #3. Now you know 2 things the time and the acceleration so you can take it from there.
 
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