Php links

[mademokid]

Right. I have successfully generate the variable I need with this code:
PHP:

$query = sprintf("SELECT id FROM ibf_members WHERE name='%s'",
    mysql_real_escape_string($username));

// Perform Query
$result = mysql_query($query);

// Check result
// This shows the actual query sent to MySQL, and the error. Useful for debugging.
if (!$result) {
    $message  = 'Invalid query: ' . mysql_error() . "\n";
    $message .= 'Whole query: ' . $query;
    die($message);
}

// Use result
// Attempting to print $result won't allow access to information in the resource
// One of the mysql result functions must be used
// See also mysql_result(), mysql_fetch_array(), mysql_fetch_row(), etc.
while ($row = mysql_fetch_assoc($result)) {
    print $row['id'];
}

// Free the resources associated with the result set
// This is done automatically at the end of the script
mysql_free_result($result);

But I need to include the $row['id'] variable in a link.

The link should be in the following format:

http://forum.example.com/index.php?showuser=$row['id']

But I don't know how to write that in php.

I would also like 'View your forum CP' to be shown as the 'link'

I hope someone understands me, because even I'm not sure!

 

[Vormund]

You use the echo/concatenate command.

Such as,
$link = "http://forum.example.com/index.php?showuser=" + $row['id'];
Then you use it wherever you want...by echoing/printing it.

Maybe...

<a href="http://forum.example.com/index.php?showuser=<?= $row['id'] ?>">View your forum CP</a>

 

[mademokid]

Thanks