I am currently putting together a computer with 2x IBM 9Gb SCSI Hard drives.
I have located the pin to set the SCSI ID, but I am still trying to work out how IBM comes up with these SCSI ID Numbers.
The pins are follows
1 ID Bit 3
2 ID Bit 2
3 ID Bit 1
4 ID Bit 0
5 Enanble Auto Spin
6 S/E Mode
7 Disable Unit ATTN
8 IT Sync Nego
9 Auto Start Delay
10 Delay Star 6 / 12
11 Disable Parity
12 Led Out
Jumpers on 5 only = SCSI ID 0
Jumpers on 5 and 4 (BIT 0) = SCSI ID 1
Jumpers on 5 and 3 (BIT 1) = SCSI ID 2
Jumpers on 5 and 2 (BIT 2)= SCSI ID 4
Jumpers on 5 and 1 (BIT 4)= Does not detect
Jumpers on 2 and 3 (BIT 2 & 3)= SCSI ID 6
Now normally I am used to the Seagate Drives where you add up the bits.
However this older IBM Drive seems to be defying that rule.
Some my question is this. What algorithm does IBM SCSI Hard Drives use to work out SCSI IDs?
Also, can some one explain to me the
* S/E Mode
* Disable Unit ATTN
* IT Sync Nego
* Auto Start Delay
* Delay Star 6 / 12
* Disable Parity
* Led Out
I have located the pin to set the SCSI ID, but I am still trying to work out how IBM comes up with these SCSI ID Numbers.
The pins are follows
1 ID Bit 3
2 ID Bit 2
3 ID Bit 1
4 ID Bit 0
5 Enanble Auto Spin
6 S/E Mode
7 Disable Unit ATTN
8 IT Sync Nego
9 Auto Start Delay
10 Delay Star 6 / 12
11 Disable Parity
12 Led Out
Jumpers on 5 only = SCSI ID 0
Jumpers on 5 and 4 (BIT 0) = SCSI ID 1
Jumpers on 5 and 3 (BIT 1) = SCSI ID 2
Jumpers on 5 and 2 (BIT 2)= SCSI ID 4
Jumpers on 5 and 1 (BIT 4)= Does not detect
Jumpers on 2 and 3 (BIT 2 & 3)= SCSI ID 6
Now normally I am used to the Seagate Drives where you add up the bits.
However this older IBM Drive seems to be defying that rule.
Some my question is this. What algorithm does IBM SCSI Hard Drives use to work out SCSI IDs?
Also, can some one explain to me the
* S/E Mode
* Disable Unit ATTN
* IT Sync Nego
* Auto Start Delay
* Delay Star 6 / 12
* Disable Parity
* Led Out