K Kitire In Runtime Messages 350 May 4, 2006 #1 http://i2.tinypic.com/x4oqr6.jpg That is just an example.. Does anyone have any links to tutorials on how to do them?
http://i2.tinypic.com/x4oqr6.jpg That is just an example.. Does anyone have any links to tutorials on how to do them?
F Fwiffo Baseband Member Messages 49 May 4, 2006 #2 yeah, i know trig, but good luck finding a tutorial, having trouble with homework or something?
E Emily Daemon Poster Messages 1,179 May 4, 2006 #3 What are you supposed to be solving for in that diagram?
F Fwiffo Baseband Member Messages 49 May 4, 2006 #4 Asking for a tutorial on trig is like saying 'Can you teach me who to do chemistry on the internet?', i have a good plan, pay attention during class
Asking for a tutorial on trig is like saying 'Can you teach me who to do chemistry on the internet?', i have a good plan, pay attention during class
K kostas In Runtime Messages 398 May 4, 2006 #5 if you drew this, you really need to learn your angles. that is nowhere near 59 degrees
aliasaid Fully Optimized Messages 2,400 May 4, 2006 #6 lmao ya thats a right angle... and as emily said what are trying to find in that diagram? and whats 48? the length of that side? i smell pythagorus..
lmao ya thats a right angle... and as emily said what are trying to find in that diagram? and whats 48? the length of that side? i smell pythagorus..
ncjimn In Runtime Messages 471 May 4, 2006 #7 I would suggest this but it might be a little too advanced. I think you have a better shot just asking the questions. I am sure someone will help you.
I would suggest this but it might be a little too advanced. I think you have a better shot just asking the questions. I am sure someone will help you.
PZEROFGH Golden Master Messages 7,689 May 4, 2006 #8 But that would just be using tan, if this is a right triangle tan = opps/adj so tan 59 = x/48 so that would be tan 59 * 48 = x then you just to x^2+48^2=y^2 and ta da you got all the sides then just 90-59 and you can get the other angle just look things up on google or us the wikipedia i found something but yeah nah
But that would just be using tan, if this is a right triangle tan = opps/adj so tan 59 = x/48 so that would be tan 59 * 48 = x then you just to x^2+48^2=y^2 and ta da you got all the sides then just 90-59 and you can get the other angle just look things up on google or us the wikipedia i found something but yeah nah
T Tordenskjold Banned Messages 237 May 5, 2006 #9 PZEROFGH said: But that would just be using tan, if this is a right triangle tan = opps/adj so tan 59 = x/48 so that would be tan 59 * 48 = x then you just to x^2+48^2=y^2 and ta da you got all the sides then just 90-59 and you can get the other angle just look things up on google or us the wikipedia i found something but yeah nah Click to expand... as a student of trig i must say... "WRONG!!!111!"
PZEROFGH said: But that would just be using tan, if this is a right triangle tan = opps/adj so tan 59 = x/48 so that would be tan 59 * 48 = x then you just to x^2+48^2=y^2 and ta da you got all the sides then just 90-59 and you can get the other angle just look things up on google or us the wikipedia i found something but yeah nah Click to expand... as a student of trig i must say... "WRONG!!!111!"
Nitestick Golden Master Messages 8,478 Location Ñмерти Ð´Ð»Ñ Ñпаме May 5, 2006 #10 :amazed: that is a pretty horrible diagram. pzero you can't use pythagorus' theorem as this is apperently not a right angled triangle. ahhhhh god i wish i could help but i can't remember the sine and cosine rule so i'm stuck to right angled triangles
:amazed: that is a pretty horrible diagram. pzero you can't use pythagorus' theorem as this is apperently not a right angled triangle. ahhhhh god i wish i could help but i can't remember the sine and cosine rule so i'm stuck to right angled triangles