computer math word problem

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GrimReaper23

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Suppose you spent a total of 16480 USD on four different Servers that you found on Ebay. The IBM Server cost was equal to the Dell Server plus half the cost of the Custom Server. The Dell Server's cost was the same as the Alienware Server minus the cost of the Custom Server. You paid three times as much for the IBM Server as you did for the Custom Server The Alienware Server cost as much as the Dell and the Custom Server put together. How much did the Alieanware Server cost?
 
The Alienware Server costs $5768.

This is how I got that answer:

IBM = a
DELL = b
Alienware = c
Custom = x

We know that:

a + b + c + x = 16480
---------------------------------
(I've summerized that paragraph into these true values: )
a = b + .5x

a = 3x

b = c - x

c = b + x

After that we can find that since a = 3x that b must equal 2.5x

So since c = b + x we can sub the b with 2.5x giving us c = 3.5x

So now we know:

a = 3x
b = 2.5x
c = 3.5x

So we sub in those values into the main equation (a+b+c+x = 16480)

This leads us to 10x = 16480

16480 divided by 10 equals 1648, so we now know that:

x = 1648

And since c = 3.5x we multiply 3.5 by 1648 which gives us 5768

So my final answer is Alienware (c) = $5768

Now my 8th grade math teacher always got on me about checking my work, so here it goes (these are the costs for all the servers):

a = 4944
b = 4120
c = 5768
x = 1648
-------------- (add those all up and you get....)
16480

God, it's 4 AM over here and I'm really tired but I can't stand not being able to do a math equation so I probably wouldn't get much sleep anyway if I didn't do this.
 
Beefcake said:
Another thing I can't stand is waiting to see if I answered it correctly. Come on Grim, wtf is the answer!

its rite, BeefCake, get some sleep, lol
 
Thanks, I don't know the answer, I will give it to you once I find out what it is. Thanks, I will put up another one later in the week.
 
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