IBMan said:
crap...
that really sucks...
I think you mis-understood what Elbatrop1 said. And I think bebop mistook a switch for a router...
Basically switches are invisible and dont have an address. At the moment you have a 4 port router, meaning that it can have 4 computers plugged into it, each of which will be assigned an address by your router, say 192.168.0.2 -> 192.168.0.5
When you plug in your switch you may gain an extra 3 ports. since the switch is invisible your router just assumes that it is now a 7 port router and assignes each of the ports an address, say 192.169.0.2 -> 192.168.0.7
Now your router has a DHCP server which assigns these addresses and can assign probably more than you will ever need. However if you are only ever going to have 4 computers on your network it makes sense to tell your router to only assign 4 addresses. This more usefull with a wireless network than a wired one but comes in useful from a security point of view since it makes it extremely hard for unauthorized users to connect to your network (it does also involves clever use of mac filtering and long lease times etc... so i wont go into it)...
What Elbatrop is saying is that if your router is set up to only assign 4 IP addresses then if you plug in a switch to increase the number of ports it will make no difference since there can still only be 4 computers plugged in because there are only 4 addresses being assigned. In which case you need to go into your router and allow it to assign more addresses. Most likely it will be set to assign the maximum number of addresses anyway, in which case you will have absolutely no problems.
Just like you can use a usb switch to give yourself more USB ports (upto 127) you can use a network switch to give yourself more network ports (up to however many addresses your router can assign - which is more than you will ever need!!)
Basically in answer to your question YES! and also yes it will be plug and go (unless you need to allow your router to assign more addresses as explained above - which is unlikely)