70-680 and would like to know how to solve a problem like this?

The /27 subnet mask is 255.255.255.224 - with the ip range of 192.168.2.32 through 192.168.2.63. The .63 is the broadcast range and .32 is the router, so the only valid IP that you could choose would be .40 - B.
 
I might of been able to solve this equation 5 months ago but since I didn't use it I forgot it :*( Need to study up on this again. Trying to study microsoft exams and cisco exams in a true PITA
 
The /27 subnet mask is 255.255.255.224 - with the ip range of 192.168.2.32 through 192.168.2.63. The .63 is the broadcast range and .32 is the router, so the only valid IP that you could choose would be .40 - B.

After just doing a couple of practice exams it came back to me easily lol. I understand now!!! Thanks for that refresh :)
 
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