e6320 overclock

[Uberg]

Hey all.

I have an Intel e6320 and a Gigabyte Ga-965p-s3 motherboard. When i got them i overclocked the e6320 to about 2.5-2.6 ghz with no problems. But recently i noticed it has reset to its default 1.86 ghz. Whenever i try to either over or underclock the processor, it restarts my computer and sets it back to 1.86. This is very annoying, does anyone know why it is happening?

Edit: sorry, i hadn't noticed there was a specific overclocking forum.

 

[turtile]

The memory may have trouble (errors or has trouble reaching a higher clock without more voltage). Which type of RAM do you have?

 

[advancedgeek]

same happens to me and also just set the system voltage to auto and system memory multiplier to 2.0.

 

[Uberg]

I have Kingston Value Ram.

Previously this did overclock absolutely fine though.

The voltage is set to auto. I will try again today.

 

[turtile]

I have Kingston Value Ram.

Previously this did overclock absolutely fine though.

The voltage is set to auto. I will try again today.

You'll have to change the divider if you want to use Value RAM. It won't be able to overclock high enough for the speeds you want.

 

[Uberg]

But i have done it before! Why did it stop working?

 

[lancec2c30]

I don't know, just try it and see if it works. Worse case is you have to set it back. o_0

 

[Uberg]

"You'll have to change the divider if you want to use Value RAM"

Can someone explain this to me?

 

[turtile]

You can change the divider settings in your BIOS. A divider allows you choose the ratio in which the memory frequency and the cpu frequency work together.

An E6320 has an 8x multiplier (8x266.66= 2.1Ghz) DDR2 533 runs as 266 x 2 = 533. So if your divider is a 1:1, both will be at 266. If you attempt to overclock, both will raise in sync. If you change the divider, you can run the memory or the CPU slower/faster than the other by the ratio chosen.

 

[Uberg]

Ah, i see. If the e6320 has an 8x multiplier, why can i only choose 6 or 7 in my BIOS?

Edit: In the bios there is no divider for memory, but a multiplier (2, 2.5, 3 etc and an "auto" option).